Question

Select the equilibrium constant expression for the following

Answer 1

The equilibrium constant expression,
`K_c`, for the reaction given in the question is written as:

• 
  `K_c = ([O_2][HF]^2)/([OF_2][H_2O])` (option B)

How to write the equilibrium constant expression?

The equilibrium constant, Kc for any given reaction is defined as the ratio of products to reactants raised to the their respective coefficients as shown below:

`K_c = ([Product]^x)/([Reactant]^y)`

Now, we shall use the above formula to determine the equilibrium constant expression for the reaction given in the question. Details below:

• Equation given:
  `OF_2(g)\ +\ H_2O(g)\ \Longleftrightarrow\ O_2(g)\ +\ 2HF(g)`
• Reactant:
  `OF_2\ and\ H_2O`
• Coefficients of reactants:
  `OF_2\ and\ H_2O` both have a coefficient of 1
• Product:
  `O_2\ and\ HF`
• Coefficients of products:
  `O_2` has a coefficient of 1 and HF has a coefficient of 2
• Equilibrium constant expression (
  `K_c`) =?

`K_c = ([O_2][HF]^2)/([OF_2][H_2O])`

Therefore, we can conclude from the above, that the correct answer to the question is option B