Slope = (y2 - y1) / (x2 - x1)
Using the coordinates of the vertices, we get:
Side AB: Slope = (3 - 0) / (0 - (-2)) = 3 / 2
Side BC: Slope = (-3 - 3) / (4 - 0) = -6 / 4 = -3/2
Side AC: Slope = (-3 - 0) / (4 - (-2)) = -3 / 6 = -1/2
So, the slopes of the sides of triangle ABC are 3/2, -3/2, and -1/2, respectively.
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