Question

If the perimeter of the rectangle shown is 60 feet, we can use the equation 8x + 4 = 60 to find its dimensions. If the solution to this equation is x = 7, what are the dimensions of the rectangle?

Answer 1

After solving the provided equation, the dimensions of the rectangle with a perimeter of 60 feet are found to be 56 feet by 2 feet when x is equal to 7.

Step-by-step explanation:

To determine the dimensions of the rectangle where the perimeter is 60 feet and the equation given is 8x + 4 = 60, we first solve for x. Since we know that x is equal to 7, we can utilize that to find the dimensions of the rectangle.

Going back to the equation:

• 8x + 4 = 60
• 8(7) + 4 = 60
• 56 + 4 = 60
• 60 = 60

With x determined as 7, we know that one pair of opposite sides of the rectangle is represented by 8x, which would be 8 times 7, giving us 56 feet. Since the perimeter is the sum of all sides and is given as 60 feet, the remaining two sides must add up to 60 - 56 = 4 feet. Because there are two sides left, each of the remaining sides must be 2 feet long.

Therefore, the dimensions of the rectangle are 56 feet by 2 feet.

Answer 2

l= 28 feet

b = 2 feet

Step-by-step explanation:

The perimeter of a rectangle is given by;

P= 2(l + b)

Comparing this to the equation; 8x + 4 = 60, i can write;

2(4x + 2) = 60

This means that;

l = 4x

b = 2

but x =7

So;

l = 4* 7 = 28 feet

b = 2 feet