Final answer:
The hybridization of fluorine varies depending on the molecule: it uses p orbitals to overlap with boron's sp² hybrid orbitals in BF3, could be thought of as having an sp³-like arrangement in CH3F, and forms bonds with central atoms that are sp³d in PF5 and sp³d² in SF6.
Step-by-step explanation:
The hybridization of the fluorine atom in different compounds varies because it adopts the hybridization that best complements the geometry of the compound. In BF3, boron is sp² hybridized and forms a trigonal planar structure; each boron's sp² hybrid orbital overlaps with a fluorine p orbital to form a sigma bond.
In CH3F, fluorine is involved in a single sigma bond with carbon and has three lone pairs, which might suggest an sp³-like arrangement around the fluorine. In PF5, the phosphorus is sp³d hybridized to form five sigma bonds, while in SF6, sulfur is sp³d² hybridized to accommodate six sigma bonds.
Fluorine typically uses its unhybridized p orbitals to form bonds with the central atom's hybrid orbitals.