Question

15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 5.40 atm. What is the new volume in liters?

Answer 1

Key words:-

• P=Pressure
• V=Volume
• T=Temperature

Here

• V1=15L
• T1=298K
• T2=383K
• P1=3.36atm
• P2=5.40atm
• V2=?

Apply combine gas law

`\\ \tt\hookrightarrow (P1V1)/(T1)=(P2V2)/(T2)`

`\\ \tt\hookrightarrow (3.36(15))/(298)=(5.40V2)/(383)`

`\\ \tt\hookrightarrow 0.169=0.014V2`

`\\ \tt\hookrightarrow V2=12.1L`