Final answer:
The maximum number of silver(Ⅰ) ions that can be present dissolved in one litre of a 0.003 Na2S solution is 0.003 moles of silver(Ⅰ) ions.
Step-by-step explanation:
The maximum number of silver(Ⅰ) ions that can be present dissolved in one litre of a 0.003 Na2S solution can be determined by calculating the concentration of silver ions in the solution and multiplying it by the volume of the solution. To do this, we need to use the stoichiometry of the dissolution equilibrium and the concentration of Na2S.
The concentration of silver ions, [Ag+], is equal to the concentration of Ag(S₂O3)2³- ions. In this case, [Ag(S₂O3)2³-] = 0.003 M.
Therefore, the maximum number of silver(Ⅰ) ions that can be present dissolved in one litre of the solution is:
0.003 M * 1 L = 0.003 moles of silver(Ⅰ) ions.