Final answer:
The atomic radius of Na is larger than Be's even with a higher Zeff, due to Na's outermost electron being in the higher 3s orbital compared to Be's 2s. Be has a higher first ionization energy because its valence electron is closer to the nucleus, experiences less shielding, and is thus more tightly held, despite Na's higher Zeff.
Step-by-step explanation:
The question pertains to effective nuclear charge (Zeff), atomic radius, and first ionization energy as they relate to the elements Beryllium (Be) and Sodium (Na).
Zeff is a measure of the net positive charge experienced by an electron in a multi-electron atom. Despite Na having a higher Zeff than Be, the atomic radius of Na is larger than Be's because Na's outermost electron is in the 3s orbital as opposed to Be's 2s orbital. The increase in the principal quantum number (n = 3 vs. n = 2) leads to a larger atomic radius due to the outer electron being further from the nucleus and experiencing more shielding from inner electrons.
Regarding first ionization energy, despite Na having a higher Zeff compared to Be, Be has a higher first ionization energy because the electron is being removed from a smaller atomic radius with less shielding, meaning it is more tightly held by the nucleus.