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I understand that AND gates require the two inputs to be present for the output to be produced. However, if one input arrives faster than the other input does the output still get produced? For example, consider the split T7 RNAP Expression System, where one input produces the T7 N-term and the second input produces the T7 C-term and both join to produce the output. So both need to be present to produce the output. If input 1 occurred first than the second input, will the output be 0 or can the N-term wait until the C-term is produced.

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Final answer:

In an AND gate, both inputs are required to be present for the output to be produced. If one input arrives first and the other input hasn't arrived yet, the output will still be '0'.

Step-by-step explanation:

In an AND gate, both inputs need to be present for the output to be produced. If one input arrives faster than the other input, the output will not be produced. This is because the AND gate requires both inputs to be true or '1' in order for the output to be true or '1'.



In the case of the split T7 RNAP Expression System, where input 1 produces the T7 N-term and input 2 produces the T7 C-term, both need to be present for the output to be produced. If input 1 occurred first, but input 2 hadn't arrived yet, the output would still be '0' because the AND gate requires both inputs to be present.

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