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For the geodesics in Schwarzschild space, I think the derivative of component time with respect to proper time is some constant (k) divided by (1-r_s/r). i.e., 1.0 minus the black hole horizon radius (r_s) divided by the radial location (r). So (k) is dimensionless? And its value at infinity (for Minkowski metric) is 1.0? Is (k) ever equal to anything other than 1.0 (in Schwarzschild space)?

User Abdou Amer
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Final answer:

The derivative of the time component in Schwarzschild space with respect to proper time involves a constant, E, relating to energy per unit mass, which equals 1.0 at infinity in Schwarzschild coordinates. E can vary inside Schwarzschild space depending on the motion conditions of the test particle, differing from the value at infinity.

Step-by-step explanation:

For the geodesics in Schwarzschild space, the derivative of the time component with respect to proper time is indeed a constant divided by the factor (1 - r_s/r), where r_s is the Schwarzschild radius and r is the radial location. The constant mentioned, often denoted by an energy parameter E, might seem dimensionless, but it is not. It reflects the energy per unit mass of a test particle in the gravitational field. At infinity, where the space-time is asymptotically flat as described by the Minkowski metric, this energy per unit mass approaches 1.0 in units where the total energy includes the rest mass energy (mc^2).

Inside the Schwarzschild space but outside the event horizon, the value of the constant k (or E) can indeed be different from 1.0 depending on the specific conditions of motion of the test particle (e.g., whether it is in a bound orbit or free-falling from infinity). In the context of the Schwarzschild solution to the Einstein field equations from the theory of general relativity, the Schwarzschild radius plays a crucial role in determining the space-time geometry around non-rotating black holes, effectively describing the event horizon from which no information can escape.

User Manmohan Badaya
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