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The quantum efficiency is a factor, telling me the ratio between optical input and electrical output. So I wondered, how does the efficiency depend on the density of the photodiod's active area? I mean the photon absorption probability is also dependent on the density of the material (+ the volume), isn't it?

How comes, that no photodiode shop provide information about the active area volume and density? Instead, they only inform about the active surface size?

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Final answer:

The quantum efficiency of a photodiode is dependent on the density of the photodiode's active area. Photodiode shops provide information about the active surface size rather than the active area volume and density.

Step-by-step explanation:

The quantum efficiency of a photodiode is indeed dependent on the density of the photodiode's active area. The density of the active area affects the probability of photon absorption, as higher density increases the chance of photon-electron interactions. However, photodiode shops typically provide information about the active surface size instead of the active area volume and density because the active surface size directly affects the collection of photons and conversion of light energy to electrical energy, making it a more relevant parameter for users.

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