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How do you know if the reaction is dominated by enthalpic or entropic factor? Do you just compare the absolute values of them? If the absolute value of ∆S is bigger than the absolute value of ∆H, can you conclude that the entropy is a more potent factor in determining the reaction progression?

User Khylo
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Final answer:

To know if a reaction is enthalpically or entropically driven, assess the Gibbs free energy change (∆G). You cannot judge the potency of entropy based on ∆S alone; temperature also plays a crucial role.

Step-by-step explanation:

To determine if a reaction is enthalpically or entropically driven, you need to consider both the enthalpy change (∆H) and the entropy change (∆S), as well as the temperature (T) at which the reaction occurs.

The spontaneity of a reaction is ultimately governed by the Gibbs free energy change (∆G), which is defined by the equation ∆G = ∆H - T∆S.

You cannot conclude that entropy is a more potent factor solely based on the comparison of the absolute values of ∆S and ∆H, because the actual impact of entropy is also influenced by the temperature.

And both ∆H and ∆S contribute to ∆G in a temperature-dependent manner.All spontaneous processes with ∆H ≥ 0 are characterized by an increase in entropy.

When ∆H is relatively small (positive or negative), the entropic contribution can dominate, making the reaction likely to proceed. In cases where ∆H is large and positive.

The entropic contribution might not be sufficient to drive the reaction forward, especially at lower temperatures.Whether a reaction is endothermic or exothermic.

And whether it is accompanied by an increase or decrease in entropy, determines the reaction's spontaneity together with the absolute temperature.

For a reaction to be spontaneous, ∆G must be negative. It is important to note that assessing the relative contribution of ∆H and ∆S requires knowing the reaction temperature.

User JJ Zabkar
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