Question

For the equilibrium expression Kc = [NH3]^2[N2][H2]^3, with initial moles and equilibrium moles given, what is the correct formula to calculate the percentage of dissociation? a) α = n_change / n_initial

b) α = n_change / n_equilibrium
c) α = n_initial / n_change
d) α = n_equilibrium / n_change

Answer 1

The correct formula to calculate the percentage of dissociation is α = n_change / n_initial. The percentage of dissociation can be calculated by determining the change in the number of moles of the reactant or product and dividing it by the initial number of moles.

Step-by-step explanation:

The correct formula to calculate the percentage of dissociation is α = n_change / n_initial.

In the given equilibrium expression, the initial moles and equilibrium moles are given for the reactants and products. The percentage of dissociation can be calculated by determining the change in the number of moles of the reactant or product and dividing it by the initial number of moles.

For example, if the initial number of moles of NH3 is 2 moles and the equilibrium number of moles is 1 mole, the change is 2 - 1 = 1 mole. The percentage of dissociation would then be 1 / 2 = 0.5 or 50%.