Final answer:
The inequality in standard form that represents the region greater than the quadratic function with zeros –3 and 6 and includes the point (–2, –16) on the boundary line is y > 2x^2 + 6x – 36.
Step-by-step explanation:
To represent the region greater than the quadratic function with zeros –3 and 6 and includes the point (–2, –16) on the boundary line, we use the inequality y > 2x^2 + 6x – 36.
To determine if the point (–2, –16) is on the boundary line, we substitute the x and y values into the quadratic function: -16 > 2(-2)^2 + 6(-2) - 36.
Simplifying this equation, we get -16 > 8 - 12 - 36, which becomes -16 > -40. Since this is true, the point (–2, –16) is on the boundary line.