Final answer:
In LS coupling, the nucleus spin momentum is considered weak and is neglected in the Russell-Saunders approximation. The Russell-Saunders approximation is efficient for lighter atoms with strong ll and appreciable ss coupling, but shifts to jj coupling for a few states of heavy atoms with weak ll and ss coupling. This preference is supported by empirical evidence and advancements in spectroscopy.
Step-by-step explanation:
In LS coupling, the total orbital momenta and total spin momenta of electrons are coupled using the Russell-Saunders approximation. In this approximation, the dependence on the positive nucleus charge Z is described by Z^4, which means it is strong. On the other hand, the coupling between the spin momentum of the nucleus and the electrons is neglected, because the nucleus spin momentum is considered weak in LS coupling.
The Russell-Saunders approximation is efficient for lighter atoms because it assumes strong ll coupling and appreciable ss coupling, which means that the orbital and spin angular momenta of electrons are strongly coupled. However, for a few states of heavy atoms, the coupling trends invert and the transition to jj coupling occurs, where the j quantum number dominates and there is weak ll and ss coupling.
The preference for the Russell-Saunders approximation in lighter atoms and the transition to jj coupling in heavy atoms is supported by empirical evidence, theoretical foundations, and advancements in spectroscopy.