Question

In a purely theoretical scenario (no gravity, etc.), consider a string with n evenly spaced points of equal weakness along the length of it. If equal tension is applied from both ends, where will it break? Will it break at each of the points of weakness thus dissecting it into n+1 pieces, or will it only snap at the outermost points of weakness, or will it snap at the centre point given n is odd? I feel like it will divide evenly at the instant the threshold force is attained.

However, if the force is first propagated through the outermost points, then those will break first immediately ending the scenario. However, I am not sure if that is how force propagation works.

Answer 1

In a scenario without gravity or any other external forces, a string with evenly spaced points of equal weakness along its length will break first at the outermost points of weakness.

Step-by-step explanation:

In a scenario without gravity or any other external forces, a string with evenly spaced points of equal weakness along its length will break first at the outermost points of weakness. In a scenario without gravity or any other external forces, a string with evenly spaced points of equal weakness along its length will break first at the outermost points of weakness.

This is because when tension is applied from both ends, the force is propagated through the string and concentrated at the points of weakness. The weakest points, which are the outermost ones, will break first, causing the string to snap into two pieces. The other points of weakness will not break unless there is additional force applied.