196k views
1 vote
In the 1948 paper by Alpher he gives a present radiation density in gm per cm cubed. How is that converted to a temp of 5 degree kelvin?

User Sneep
by
8.2k points

1 Answer

4 votes

Final answer:

The Stefan-Boltzmann law relates the radiation an object emits to its temperature. Additional constants and considerations are required to convert from radiation density to temperature, as the student's question implies a relationship between mass density and temperature.

Step-by-step explanation:

The question refers to converting radiation density, given in mass per unit volume, to a temperature, which is measured in degrees Kelvin. The Stefan-Boltzmann law explains the relationship between an object's temperature and the energy it radiates. The law's formula is P = σeAT4, where σ is the Stefan-Boltzmann constant, e refers to the emissivity of the object, A is its surface area, and T is its absolute temperature in Kelvin.

To convert the given radiation density to temperature, one would need to consider other constants, such as those provided related to energy per Kelvin, the speed of light in meters per second, the Coulomb force between electric charges, and mass-energy equivalence values. These constants are instrumental in the equations involving black body radiation, where they could potentially be used alongside the Stefan-Boltzmann law.

User Ovgolovin
by
8.3k points