Final answer:
The angular acceleration of the motorcycle wheel after release can be found using the formula a = net τ/I, where τ is the torque and I is the moment of inertia of the wheel.
Step-by-step explanation:
To find the angular acceleration of the motorcycle wheel just after release, we apply the rotational analogue of Newton's second law, which states that angular acceleration is equal to the net torque divided by the moment of inertia (a = net τ/I).
Given that the drive chain exerts a force (F) of 2200 N at a radius (r) of 0.05 m, we can calculate the torque (τ = F * r). Using the given mass (m) of the wheel and the inner (r1) and outer (r2) radii, we can calculate the moment of inertia (I) for an annular ring using the equation I = m * (r1^2 + r2^2) / 2. Once we have the torque and moment of inertia, we can use the formula to find the angular acceleration (a).