Question

Identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)² – 3. A. vertex: (2, -3); axis of symmetry: x = 2 B. vertex: (-2, -3); axis of symmetry: x = -2 C. vertex: (2, 3); axis of symmetry: x = 2, vertex: (−2, 3); axis of symmetry: x = -2

URGENT ​

Answer 1

B

Explanation:

Vertex form of a quadratic:

`y=a(x-h)^2+k`

Actual equation:

`y=3(x+2)^2-3`

This function can be rewritten as:


`y=3(x-(-2))^2+(-3)`

here, h=-2 and k=-3

the vertex is (h,k) so the vertex is (-2,-3) and the axis of symmetry is x=h. So the axis of symmetry is x=-2.

hope this helps!