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Let us consider the transition form factor of proton to Delta

γ∗p→Δ.

Then we should also have the timelike transtion form factor of antiproton and Delta:

γ∗→p¯Δ,

However, the Charge congjuation of the photon is -, and p¯Δ
system does not have Charge congjuation, so how can we understand the Charge congjuation in γ∗→p¯Δ?

User Fuweichin
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Final answer:

The charge conjugation is not necessary in the timelike transition form factor of γ∗→p¯Δ due to the consistent interaction with the charge of the antiproton.

Step-by-step explanation:

The charge conjugation in the timelike transition form factor of antiproton and Delta can be understood by considering the properties of the particles involved. The charge conjugation of the photon is negative (-), and it interacts with the positive charge of the proton. In the case of the antiproton, which has a negative charge, the charge conjugation is not needed because the interaction with the photon is already consistent with the sign of the charge. Therefore, the charge conjugation is not necessary in the transition form factor of γ∗→p¯Δ.

Charge conjugation is a fundamental concept in theoretical physics, particularly in the field of quantum mechanics and quantum field theory. It is one of several discrete symmetries that describe the behavior of physical systems.

Charge conjugation, denoted by the symbol

C, is a transformation that changes particles into their corresponding antiparticles by reversing their charges. In other words, if you apply charge conjugation to a particle, it becomes its antiparticle, and vice versa. For example, the charge conjugation of an electron (

e

) is a positron (

+

e

+

), and vice versa.

User CosminO
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