Question

So I want to find if this fulfills the counting criteria of Support Reaction + Intermediate Reactions =2∗2∗Elements There are 3 elements and 5 Support reactions but I cannot understand how there are 6 Intermediate reactions! Intermediate Reactions =2∗(n−1)2∗(n−1)where is the number of elements coming out of a node. There are only 2 nodes in the middle and each have 3 joints so shouldn't I be=2∗(3−1)+2∗(3−1)=8?I=2∗(3−1)+2∗(3−1)=8?

Answer 1

The formula given for calculating the number of intermediate reactions in a system is not correct. The correct formula for calculating the number of intermediate reactions is 2*(n-1), where n is the number of nodes in the system.

Step-by-step explanation:

The formula given for calculating the number of intermediate reactions in a system is not correct. The correct formula for calculating the number of intermediate reactions is 2*(n-1), where n is the number of nodes in the system.

In this case, you mentioned that there are 2 nodes, each having 3 joints. Therefore, the correct calculation would be 2*(3-1) which equals 4, not 6. The formula given for calculating the number of intermediate reactions in a system is not correct. The correct formula for calculating the number of intermediate reactions is 2*(n-1), where n is the number of nodes in the system.

So, the counting criteria for Support Reaction + Intermediate Reactions = 2*2*Elements is fulfilled with 3 elements, 5 support reactions, and 4 intermediate reactions.