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How do you name:HOOC−CHX2−CO−CHX2−CHX2−CHX2−CHOH−CHO Will the name for this be 8-formyl-3-oxo-7-hydroxyoctanoic acid? Or will there be some specific changes regarding the concentration of the groups on one side or some other change I am unaware of?

User HDiamond
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Final answer:

The correct name for the molecule should include octanedioic acid as the base name with prefixes and suffixes indicating the presence of formyl, substituents represented by 'X', and the hydroxy group, leading to a name such as '8-formyl-2,4,5,6-tetraX-7-hydroxyoctanedioic acid', where X is replaced with the corresponding halogen.

Step-by-step explanation:

The correct IUPAC name for the molecule HOOC-CHX2-CO-CHX2-CHX2-CHX2-CHOH-CHO should account for all functional groups and substituents while following proper nomenclature rules. When naming this molecule, we consider the presence of two carboxylic acid groups, implying the suffix 'dioic acid'. The longest carbon chain is octane, because it contains eight carbon atoms as well as the carboxylic acid groups, making the root name 'octanedioic acid'.

The molecule also contains a formyl group (CHO) at the eighth carbon, thus '8-formyl'. Additionally, there are four identical substituents (CHX2) which should be named as 'fluoro, chloro, bromo, or iodo' depending on what X represents. We need to find the respective locations of each substituent and list them in numerical order followed by the substituent name.

User Mpratt
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