Question

Triplet A stays on the earth. Triplet B travels at speed 4c/5 to a planet

(a distance L away) and back. Triplet C travels out to the planet at speed

3c/4, and then returns at the necessary speed to arrive back exactly

when B does. How much does each triplet age during this process?

Who is youngest?
Options:
A) Triplet A ages the most, Triplet B ages less, and Triplet C ages the least.
B) Triplet A ages the least, Triplet B ages more than A but less than C, and Triplet C ages the most.
C) Triplet A, B, and C age the same due to time dilation effects canceling each other out.
D) Triplet A ages the least, Triplet B and Triplet C age the same, but more than A.

Answer 1

Triplet A ages the most, Triplet B ages less, and Triplet C ages the least.

Step-by-step explanation:

The question asks about the age of each triplet during a space travel scenario involving time dilation due to relativistic speeds.

Triplet A stays on Earth, while Triplet B travels at a speed of 4c/5 to a planet L away and then returns. Triplet C travels to the same planet at a speed of 3c/4 and returns at the necessary speed to arrive back exactly when B does.

According to the theory of relativity, time dilation occurs at high speeds, meaning that time moves slower for objects in motion.

As a result, Triplet B, who ages less, will be the youngest. Triplet C will age more than B but less than A, so C will be the second youngest. Triplet A, who remains on Earth, ages the most and will be the oldest.