Question

A 2g pillow is thrown through the air with an acceleration of 8m/s2

Answer 1

The distance traveled by the pillow subjected to 8 m/s^2 acceleration can be determined by specifying the time (t). For instance, with t = 2 seconds, the distance would be 8 meters.

To determine the distance traveled by an object under constant acceleration, you can use the kinematic equation:

`\[ d = ut + (1)/(2)at^2 \]`

where:

- d is the distance traveled,

- u is the initial velocity,

- a is the acceleration,

- t is the time.

Assuming the pillow starts from rest u = 0, the equation simplifies to:

`\[ d = (1)/(2)at^2 \]`

Given that the acceleration a is
`\( 8 \, \text{m/s}^2 \)` and the time t is not provided, we can't calculate the exact distance without that information. If you have the time the pillow is subjected to the acceleration, you can plug in that value into the equation to find the distance.

For example, if t = 2 s, the calculation would be:

`\[ d = (1)/(2) * 8 \, \text{m/s}^2 * (2 \, \text{s})^2 \]`

`\[ d = (1)/(2) * 8 \, \text{m/s}^2 * 4 \, \text{s}^2 \]`

d = 8 m

So, the distance traveled would be 8 m in this example.

Complete question:

How far will a 2g pillow travel through the air when subjected to an acceleration of 8 m/s²?