The Voltage across circuit is 13.21 V. Power dissipated by R1 is 0.21 V. Current through R1 is 0.02 A. Current through R2 is 0mA. R1 = 60.5 Ω. R2 = 2.05 Ω
To solve for the DC circuit component values in the image, we can use the following steps:
1. Label the currents and voltages. We are given that the voltage across the entire circuit is 13.21 V and the power dissipated by R1 is 0.21 W. We can also see that the current through R2 is 0 mA. Therefore, label the values.
2. Apply Kirchhoff's Voltage Law (KVL) to the loop. KVL states that the algebraic sum of the voltages around any closed loop in a circuit must be zero. Therefore, we can write the following equation:
13.21 V - I1 * R1 - 0.21 V = 0
3. Solve for R1. We can solve the above equation for R1 as follows:
R1 = (13.21 V - 0.21 V) / I1
To solve for I1, we can use the following equation:
I1 = P / V1
where P is the power dissipated by R1 and V1 is the voltage across R1. Therefore, we can substitute these values into the equation for R1 to get the following:
R1 = (13.21 V - 0.21 V) / (0.21 W / 13.21 V)
R1 = 60.5 Ω
4. Apply KVL to the second loop. We can apply KVL to the second loop in the circuit to write the following equation:
0.21 V - I2 * R2 = 0
5. Solve for R2.We can solve the above equation for R2 as follows:
R2 = 0.21 V / I2
To solve for I2, we can use the following equation:
I2 = (P1 - P2) / V
where P1 is the power dissipated by the entire circuit, P2 is the power dissipated by R1, and V is the voltage across the entire circuit. Therefore, we can substitute these values into the equation for R2 to get the following:
R2 = 0.21 V / ((1.31 W - 0.21 W) / 13.21 V)
R2 = 2.05 Ω
Therefore, the values of the DC circuit components are as follows:
R1 = 60.5 Ω
R2 = 2.05 Ω