Question

3. CONSTRUCTION A rectangular deck is built

around a square pool. The pool has side length s. The


length of the deck is 5 units longer than twice the side


length of the pool. The width of the deck is 3 units


longer than the side length of the pool. What is the


area of the deck in terms of s?





Did I do this right or was I supposed to leave it as a trinomial?

Answer 1

`s^2+11s+15`

Explanation:

Let side length of pool=s

According to question

Length of rectangular deck , l=2s+5

Width of rectangular deck, b=3+s

We have to find the area of deck in terms of s.

We know that

Area of square=
`(side)^2`

Area of rectangle=
`l* b`

Using the formula

Area of pool=
`s^2`

Area of (rectangular deck+ pool)=
`(2s+5)(3+s)`

Now,

Area of rectangular deck

=
`(2s+5)(3+s)-s^2`

`=6s+2s^2+15+5s-s^2`

=
`s^2+11s+15`