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If the rate of replication in a particular prokaryote is 900 nucleotides per second, how long would it take 1.2 million base pair genomes to make two copies?

a) 6.67 minutes.
b) 2.22 minutes.
c) 13.33 minutes.
d) 4.44 minutes.

User Chinatsu
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1 Answer

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Final answer:

To replicate a 1.2 million base pair genome twice in a prokaryote with a replication rate of 900 nucleotides per second, it would take 44.44 minutes. This was calculated by multiplying the total number of base pairs by 2 to get the total number of nucleotides needed and then dividing that by the rate of replication.

Step-by-step explanation:

To calculate the time required for the replication of a prokaryote's genome, we must understand that replication involves adding nucleotides to the DNA strand at a certain rate. Given that the replication rate of this prokaryote is 900 nucleotides per second and the entire genome is 1.2 million base pairs, we can do the following calculation:

Total number of nucleotides to replicate = 1.2 million base pairs x 2 (for both copies) = 2.4 million nucleotides.

Now, to find the time taken, we can divide the total nucleotides by the rate of replication:

Time (seconds) = 2.4 million nucleotides / 900 nucleotides per second.

Time (seconds) = 2666.67 seconds.

To convert seconds into minutes, we divide by 60:

Time (minutes) = 2666.67 seconds / 60 seconds per minute.

Time (minutes) = 44.44 minutes.

Hence, it would take 44.44 minutes to make two copies of a 1.2 million base pair genome at the given rate of replication in a prokaryotic cell.

User Poornan
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