Final answer:
Using the probability method, the offspring of a cross between AABBCc and Aabbcc have equal proportions (1/4 each) for the following genotypes: AABbCc, AABbcc, AaBbCc, and AaBbcc (Option A).
Step-by-step explanation:
To calculate the genotypes and genotypic proportions of a cross between AABBCc and Aabbcc, we use the probability method.
This approach considers each gene independently and applies the product rule for independent assortment.
The parent genotypes can contribute different alleles to their offspring, with AABBCc parent only contributing A, B, and either C or c, while Aabbcc can only contribute a, b, and c alleles.
The genotypes of the offspring from this cross would be:
- AABbCc (A from the first parent, A and b from the second parent, Cc from both parents)
- AABbcc (A from the first parent, A and b from the second parent, cc from the second parent)
- AaBbCc (Aa from both parents, B from the first parent, Cc from both parents)
- AaBbcc (Aa from both parents, B from the first parent, cc from the second parent)
The proportions for each genotype are:
- AABbCc - 1/4
- AABbcc - 1/4
- AaBbCc - 1/4
- AaBbcc - 1/4
Thus, the correct option based on the parent genotypes AABBCc and Aabbcc is Option A.