Final answer:
In Boron-10, the Pauli Exclusion Principle dictates that nucleons must occupy unique quantum states, while Hund's Rule suggests spins align to maximize total spin. Clebsch-Gordan coefficients then describe the combinations of these individual spins to yield a nuclear spin of 3.
Step-by-step explanation:
The question pertains to the nuclear spin of Boron-10 and how principles like the Pauli Exclusion Principle, Hund's Rule, and the use of Clebsch-Gordan coefficients interact to give it a nuclear spin of 3. Boron-10 has 5 protons and 5 neutrons. According to the Pauli Exclusion Principle, no two identical fermions (which protons and neutrons are) can occupy the same quantum state simultaneously.
Thus, within a nucleus, protons and neutrons will fill available nuclear shell states with their spins aligned to maximize total spin, adhering to nuclear shell models. When particles combine their angular momenta, such as spins in a nucleus, the resultant possible states are given by Clebsch-Gordan coefficients, which help to predict the resulting spins after the combination of two angular momenta. Specifically, these coefficients are used in quantum mechanics to construct the spin state of a composite system like a nucleus from the individual spins of the particles.