Final answer:
The distance traveled by the mobile is 12960005 m.
Step-by-step explanation:
To calculate the distance traveled by a mobile with an initial velocity of 5 m/s, a constant acceleration of 2 m/s², and a time of 1 hour, we can use the formula:
d = v₀t + (1/2)at²
Where:
- d is the distance
- v₀ is the initial velocity
- t is the time
- a is the acceleration
Plugging in the given values, we have:
d = (5 m/s)(1 hr) + (1/2)(2 m/s²)(1 hr)²
d = 5 m + (1/2)(2 m/s²)(3600 s)²
d = 5 m + (1/2)(2 m/s²)(12960000 s²)
d = 5 m + 1/2(25920000 m)
d = 5 m + 12960000 m
d = 12960005 m