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25x^2 - 20x + 4 = 0 HELPPPPPPPP THIS IS DUE TMRR

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The quadratic equation 25x^2 - 20x + 4 = 0 can be solved using the quadratic formula. The solution is x = 0.4.

This expression is a quadratic equation of the form at² + bt + c = 0, where the constants are a = 25, b = -20, and c = 4.

To find the solutions, we can use the quadratic formula: x = (-b ± √(b² - 4ac)) / (2a).

Substituting the values of a, b, and c into the formula, we get: x = (-(-20) ± √((-20)² - 4(25)(4))) / (2(25)).

Simplifying further, we have: x = (20 ± √(400 - 400)) / 50.

Since the discriminant (b² - 4ac) is equal to zero, there is only one solution.

Therefore, the solution to the equation is x = 0.4.

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