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Triangle ABD~ triangle DBC the perimeter of triangle ABD=36, fond the perimeter of triangle DBC.

Triangle ABD~ triangle DBC the perimeter of triangle ABD=36, fond the perimeter of-example-1
User Ceej
by
7.5k points

1 Answer

7 votes

Answer:

Perimeter of ΔDBC = 48 units

Explanation:

It's given in he question,

ΔABD ~ ΔDBC

Therefore, by the definition of similar triangles,

Corresponding sides of both the triangle will be proportional.


(AB)/(DB)= (BD)/(BC)= (AD)/(DC)


(9)/(12)= (12)/(16)= (AD)/(DC)


(3)/(4)=(AD)/(DC)

AD =
(3)/(4)DC ----------(1)

Since, perimeter of ΔABD = 36,

AB + BD + AD = 36

9 + 12 + AD = 36

AD = 36 - 21

AD = 15

From equation (1),

15 =
(3)/(4)(DC)

DC = 20

Perimeter of ΔDBC = DB + BC + DC

= 12 + 16 + 20

= 48

Therefore, perimeter of ΔDBC = 48 units is the answer.

User Latifah
by
8.8k points
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