Question

Ay we have 3 equal bodies in contact, and there is a heat engine that absorbs and emits heat to these 3 bodies and it does work to an external medium.

How would that work? I imagine that it would get to a final temperature between the 3 bodies, and it could be found with
Q_A+Q_B+Q_C+W_{engine}=Δ U

But I have no clue

Answer 1

When three equal bodies in contact are connected to a heat engine, the work done by the engine can be calculated using the first law of thermodynamics. The change in internal energy for the cycle is zero.

Step-by-step explanation:

When three equal bodies in contact are connected to a heat engine, the engine absorbs heat from these bodies and does work on an external medium. When three equal bodies in contact are connected to a heat engine, the work done by the engine can be calculated using the first law of thermodynamics. The change in internal energy for the cycle is zero.

The work done by the engine can be calculated using the first law of thermodynamics as W = Q_A + Q_B + Q_C, where Q_A, Q_B, and Q_C are the heat absorbed by each body. The change in internal energy (ΔU) for the cycle is zero since the initial and final states of the system are the same.