Final answer:
The right ratio for the combustion of kerosene and hydrogen peroxide depends on the stoichiometry of the reactions. For a 50% pure hydrogen peroxide, the amount used needs to be halved to achieve the desired ratio.
Step-by-step explanation:
The right ratio for the combustion of kerosene and hydrogen peroxide will depend on the specific experiment and the desired outcome. Generally, when it comes to the combustion of liquids, the ratio is determined by the stoichiometry of the reaction, which involves balancing the equation and determining the molar ratios between the reactants and products. In the case of the combustion of kerosene, the balanced equation would be:
{C₁₂H₂₃} + {O₂} -> {CO₂} + {H₂O}
Where {C₁₂H₂₃} represents kerosene.
The ratio of kerosene to oxygen can be determined by comparing the coefficients in the balanced equation. For example, if the coefficient of kerosene is 1, and the coefficient of oxygen is 12, the ratio would be 1:12.
Similarly, the combustion of hydrogen peroxide can be represented by the equation:
{H₂O₂} -> {H₂O} + {O₂}
Where {H₂O₂} represents hydrogen peroxide.
The ratio of hydrogen peroxide to water can be determined by comparing the coefficients in the equation. In this case, the ratio would be 1:1.