188k views
1 vote
. A waste contains 50 mg/L of phenol (C6H6O). Determine the carbonaceous theoretical oxygen demand of the waste.

1 Answer

2 votes

The carbonaceous theoretical oxygen demand of the waste is \(25 \, \text{mg/L}\).

The carbonaceous theoretical oxygen demand (CTOD) is an estimate of the amount of oxygen needed to oxidize the organic carbon present in a waste.

The formula for calculating CTOD is:

\[ CTOD = \frac{{\text{Concentration of Carbon (mg/L)}} \times \text{Stoichiometric Coefficient}}{\text{Molecular Weight of Carbon (mg/mmol)}} \]

For phenol (C6H6O), the stoichiometric coefficient for carbon is 6, and the molecular weight of carbon is \(12 \, \text{g/mol}\).

\[ CTOD = \frac{{50 \, \text{mg/L} \times 6}}{{12 \, \text{mg/mmol}}} \]

\[ CTOD = \frac{{300}}{{12}} \]

\[ CTOD = 25 \, \text{mg/L} \]

Therefore, the carbonaceous theoretical oxygen demand of the waste is \(25 \, \text{mg/L}\).

User Eshita Shukla
by
8.1k points