184k views
3 votes
8,000 at 4% compounded semi annually for 9 years

User Maxlk
by
8.1k points

1 Answer

2 votes

Final answer:

To have $10,000 in ten years in a bank account that pays 10% interest compounded annually, you need to put in $3,854.91.

Step-by-step explanation:

To find out how much money you have to put into a bank account that pays 10% interest compounded annually to have $10,000 in ten years, you can use the compound interest formula. The formula is:

A = P(1 + r/n)^(nt)

Where A is the future value, P is the principal (the initial amount of money), r is the annual interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the number of years.

In this case, we know that the future value (A) is $10,000, the annual interest rate (r) is 0.10, and the number of years (t) is 10. We need to solve for the principal (P).

Plugging in the values into the formula:

$10,000 = P(1 + 0.10/1)^(1*10)

$10,000 = P(1.10)^10

Dividing both sides of the equation by (1.10)^10:

P = $10,000 / (1.10)^10

P = $10,000 / 2.5937

P = $3,854.91

User Sacha Nacar
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories