Final answer:
The rate law expression for a reaction that is second-order in compound A is Rate = k[A]², where the rate is proportional to the square of the concentration of A.The correct answer is option A.
Step-by-step explanation:
The reaction of compound A to give compounds C and D was found to be second-order in A. The rate law expression for this reaction is given by the expression:Rate = k[A]²
Since the reaction is second-order in A, it implies that the rate of the reaction is directly proportional to the square of the concentration of A. In the case where two A molecules collide and react, the rate of this bimolecular reaction would be represented as k[A]², to show it’s second-order in A.
It is important to note that unlike zero-order reactions, where the rate is independent of the concentration of the reactants, or first-order reactions, where the rate is directly proportional to the concentration of a single reactant
Second-order reactions involve the concentration of one reactant raised to the second power or the product of the concentrations of two different reactants.The correct answer is option A.