Final answer:
The mass of water displaced by the bird bone is 41.40 g, calculated by subtracting the apparent mass when submerged from the mass in air. The volume of the bone equals the mass of water displaced, 41.40 cm³, due to the density of water being 1 g/cm³. The average density of the bone is found by dividing its mass by its volume.
Step-by-step explanation:
The question involves applying principles of physics, specifically Archimedes' principle, to determine the properties of a bird bone based on its mass in air and apparent mass when submerged in water. The problem includes finding the mass of water displaced, the volume, and the average density of the bird bone.
- The mass of water displaced can be found by subtracting the apparent mass of the bird bone when submerged from its mass in air.
- The volume of the bone is equivalent to the volume of the displaced water, which can be calculated from the mass of water displaced.
- The average density of the bird bone can then be determined by dividing the mass of the bone by its volume.
To answer the questions given, we proceed as follows:
- Mass of water displaced = Mass of bone in air - Apparent mass of bone in water = 45.0 g - 3.60 g = 41.40 g.
- Volume of the bone = Mass of water displaced (since the density of water is 1 g/cm³) = 41.40 cm³.
- Average density of the bone = Mass of the bone / Volume of the bone = 45.0 g / 41.40 cm³.
The correct answer for the mass of water displaced is 41.40 g (Option A).