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The aqueous humor in a person’s eye is exerting a force of 0.300 N on the 1.10-cm² area of the cornea.

(a) What pressure is this in mm Hg?
(b) Is this value within the normal range for pressures in the eye?

User Qtngo
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Final answer:

The pressure exerted by the aqueous humor on the cornea is calculated to be 20.5 mm Hg, which is within the normal range for eye pressure of 12-24 mm Hg.

Step-by-step explanation:

The aqueous humor in a person's eye is exerting a force of 0.300 N on a 1.10-cm² area of the cornea. To find the pressure in mm Hg, we use the formula P = F/A, where P is the pressure, F is the force, and A is the area. First, we convert the area from cm² to m². Thus, 1.10 cm² = 1.10 x 10⁻⁴ m² (since 1 cm² = 10⁻⁴ m²). Now, the pressure in pascals is:

P = 0.300 N / 1.10 x 10⁻⁴ m² = 2.727 x 10³ Pa

To convert from pascals to mm Hg, we use the conversion factor: 1 mm Hg is approximately equal to 133.322 Pa. Thus:

P in mm Hg = 2.727 x 10³ Pa / 133.322 Pa/mm Hg = 20.5 mm Hg

As for the normal range of eye pressure, it is considered to be between 12-24 mm Hg. The calculated pressure of 20.5 mm Hg is within this normal range, indicating that the pressure in the eye does not signify an abnormality related to conditions like glaucoma, which can have much higher pressures.

User Vgunnu
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