Question

When a disk between spinal vertebrae is subjected to a compressional force of 5000 N, the pressure created, assuming a uniform circular cross-section with a radius of 2.00 cm, is approximately:

a. 3.98 × 10^6 Pa
b. 7.96 × 10^6 Pa
c. 1.99 × 10^7 Pa
d. 3.98 × 10^7 Pa

Answer 1

The pressure created when a disk between spinal vertebrae is subjected to a compressional force can be calculated using the formula P = F/A, where P is the pressure,

F is the force, and A is the area. In this case, the pressure is approximately 3.98 × 10^6 Pa.

Step-by-step explanation:

When a disk between spinal vertebrae is subjected to a compressional force, the pressure created can be calculated using the formula P = F/A, where P is the pressure, F is the force, and A is the area.

In this case, the force is 5000 N and the disk has a uniform circular cross-section with a radius of 2.00 cm. To find the area, we can use the formula A = πr², where r is the radius.

Plugging in the values, we get:

A = π(2.00 cm)² = 12.57 cm²

P = (5000 N) / (12.57 cm²) = 3980 Pa

Therefore, the pressure created is approximately 3.98 × 10^6 Pa.