Question

What is the rate constant (k) for the reaction Q ⟶ W + X?

a. 6.68 × 10^(-3) mol L^(-1) s^(-1)
b. 1.04 × 10^(-2) mol L^(-1) s^(-1)
c. 2.94 × 10^(-2) mol L^(-1) s^(-1)
d. 1.74 × 10^(-2) mol L^(-1) s^(-1)

Answer 1

The rate constant (k) for the reaction Q ⟶ W + X is approximately 1.12 mol/(L s).

Step-by-step explanation:

The rate law for the reaction Q → W + X can be determined using the given data. Based on the data, the rate of the reaction is directly proportional to the initial concentration of Q. Therefore, the reaction is considered to be first order with respect to Q. The rate law can be written as rate = k[Q], where k is the rate constant.

Let's calculate the values of the rate constant for the different initial concentrations of Q:

1. Using the data point [Q]initial = 0.170 M and Rate = 0.212 mol/(L s), we can substitute these values into the rate law equation: 0.212 = k(0.170). Solving for k, we get k = 1.247 mol/(L s).
2. Using the data point [Q]initial = 0.212 M and Rate = 0.212 mol/(L s), we can substitute these values into the rate law equation: 0.212 = k(0.212). Solving for k, we get k = 1 mol/(L s).

Since the rate constant should be consistent for the reaction, we could take the average of the two calculated values for k: (1.247 + 1) / 2 = 1.1235. Therefore, the rate constant (k) for the reaction Q → W + X is approximately 1.12 mol/(L s).