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You are pumping up a bicycle tire with a hand pump, the piston of which has a 2.00-cm radius.

(a) What pressure is exerted by the hand pump piston?
a) 3.18 × 10⁴ Pa
b) 7.96 × 10² Pa
c) 1.59 × 10⁵ Pa
d) 3.98 × 10³ Pa

1 Answer

6 votes

Final answer:

The pressure exerted by the hand pump piston is 8.67 × 10^4 Pa.

Step-by-step explanation:

To calculate the pressure exerted by the hand pump piston, we can use the equation:

Pressure = Force / Area

Since the piston has a radius of 2.00 cm, the area can be calculated using the formula for the area of a circle:

Area = π * radius^2

Substituting the values, we get:

Area = π * (2.00 cm)^2

Area = 12.57 cm^2

Now, we can calculate the force exerted by the hand pump piston using the equation:

Force = Pressure * Area

Substituting the given pressure value of 6.90 × 10^5 Pa and the calculated area value, we get:

Force = 6.90 × 10^5 Pa * 12.57 cm^2

Force = 8.67 × 10^4 N

Therefore, the pressure exerted by the hand pump piston is 8.67 × 10^4 Pa.

User Chris Olson
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