192k views
3 votes
A 1.80-kg falcon catches a 0.650-kg dove from behind in midair. What is their velocity after impact if the falcon’s velocity is initially 28.0 m/s and the dove’s velocity is 7.00 m/s in the same direction?

User SubmarineX
by
8.1k points

1 Answer

1 vote

Final answer:

The final velocity after the falcon catches the dove is 22.4 m/s.

Step-by-step explanation:

To find the final velocity after the falcon catches the dove, we can use the principle of conservation of momentum. The momentum before the impact is equal to the momentum after the impact.

Using the equation:

m1 * v1 + m2 * v2 = (m1 + m2) * vf

where m1 and m2 are the masses of the falcon and the dove, v1 and v2 are their respective velocities before the impact, and vf is the final velocity after the impact.

Plugging in the values:

(1.80 kg * 28.0 m/s) + (0.650 kg * 7.00 m/s) = (1.80 kg + 0.650 kg) * vf

Simplifying the equation:

50.4 kg*m/s + 4.55 kg*m/s = 2.45 kg * vf

54.95 kg*m/s = 2.45 kg * vf

vf = 22.4 m/s

Therefore, the velocity of the falcon and the dove after the impact is 22.4 m/s.

User BlueYoshi
by
8.7k points