Question

Integrated Concepts A 35.0-kg dolphin decelerates from 12.0 to 7.50 m/s in 2.30 s to join another dolphin in play. What average force was exerted to slow him if he was moving horizontally? (The gravitational force is balanced by the buoyant force of the water.) What average force was exerted to decelerate the 35.0-kg dolphin from 12.0 to 7.50 m/s in 2.30 s, assuming horizontal motion?

a) 33 N
b) 42 N
c) 55 N
d) 67 N

Answer 1

The average force exerted to slow down the dolphin is approximately -33 N.

Step-by-step explanation:

To calculate the average force exerted to slow down a dolphin, we can use Newton's second law of motion which states that force equals mass multiplied by acceleration. In this case, the acceleration can be calculated by taking the difference in velocities and dividing it by the time taken. The mass of the dolphin is given as 35.0 kg. The average force can be calculated by multiplying the mass by the acceleration. So, the average force exerted to slow down the dolphin is:

F = m * a

F = (35.0 kg) * ((7.50 m/s - 12.0 m/s) / 2.30 s)

F ≈ -33 N

Since the dolphin is decelerating, the force is negative. Therefore, the average force exerted to slow down the dolphin is approximately -33 N.