Final answer:
To estimate the terminal velocity of the squirrel, we can use the formula v = sqrt((2mg)/(ρAC)).
With the given values, the terminal velocity of the squirrel is estimated to be approximately 11.3 m/s.
However, without the cross-sectional area and drag coefficient for the person, we cannot accurately estimate their velocity without drag contribution.
Step-by-step explanation:
To estimate the terminal velocity of the squirrel, we need to use the formula:
v = sqrt((2mg)/(ρAC))
Where:
- v is the terminal velocity
- m is the mass of the squirrel (in kg)
- g is the acceleration due to gravity (approximately 9.8 m/s^2)
- ρ is the density of air (approximately 1.225 kg/m^3)
- A is the cross-sectional area facing the fluid (in m^2)
- C is the drag coefficient (approximately 1 for a horizontal skydiver)
Calculating with the given values:
- m = 0.56 kg
- A = 0.144 cm^2 = 0.144 x 10^-4 m^2
- C = 1
Plugging the values into the formula, we get
v = sqrt((2 * 0.56 * 9.8) / (1.225 * 0.144 x 10^-4))
v ≈ 11.3 m/s
To estimate the velocity of the person, we need to use the formula:
v = sqrt((2mg)/(ρAC))
Calculating with the given values:
- m = 56 kg (Note: Convert grams to kilograms)
- A = ? (not provided in the question)
- C = ? (not provided in the question)
Since the question does not provide the cross-sectional area and the drag coefficient for the person, we cannot accurately estimate the velocity without this information. Therefore, we cannot determine the velocity of the person hitting the ground without drag contribution.