Question

A baseball pitcher brings his arm forward during a pitch, rotating the forearm about the elbow. If the velocity of the ball in the pitcher’s hand is 35.0 , {m/s}, and the ball is 0.300 , {m} from the elbow joint, what is the angular velocity of the forearm?

A. 116.7 , {rad/s}
B. 105.2 , {rad/s}
C. 96.7 , {rad/s}
D. 85.1 , {rad/s}

Answer 1

The angular velocity of the forearm is 116.7 rad/s.

Step-by-step explanation:

To find the angular velocity of the forearm, we can use the equation:

angular velocity = linear velocity / radius

In this case, the linear velocity of the ball in the pitcher's hand is 35.0 m/s and the distance from the elbow joint to the ball is 0.300 m. Plugging these values into the equation gives us:

angular velocity = 35.0 m/s / 0.300 m = 116.7 rad/s

So, the angular velocity of the forearm is 116.7 rad/s.