Question

In lacrosse, a ball is thrown from a net on the end of a stick by rotating the stick and forearm about the elbow. If the angular velocity of the ball about the elbow joint is 30.0 , {rad/s}, and the ball is 1.30 , {m} from the elbow joint, what is the velocity of the ball?

A. 39.0 , {m/s}
B. 35.0 , {m/s}
C. 31.5 , {m/s}
D. 28.3 , {m/s}

Answer 1

The linear velocity of the ball in lacrosse when thrown from a net at an angular velocity of 30.0 rad/s and at a distance of 1.30 m from the elbow joint is 39.0 m/s.

Step-by-step explanation:

In lacrosse, when a ball is thrown by rotating the stick and forearm about the elbow, its linear velocity can be calculated using the formula for the tangential velocity in rotational motion, which is v = r * ω, where v is the linear velocity, r is the radius from the pivot point to the point of interest (in this case, the ball), and ω is the angular velocity. Given an angular velocity of 30.0 rad/s and a distance from the elbow joint to the ball of 1.30 m, the velocity of the ball is calculated as follows:

v = r * ω = 1.30 m * 30.0 rad/s = 39.0 m/s

Thus, the linear velocity of the ball is 39.0 m/s, which corresponds to answer option A.