Question

Integrated Concepts An elevator filled with passengers has a mass of 1700 kg. (a) The elevator accelerates upward from rest at a rate of 1.20 m/s2 for 1.50 s. Calculate the tension in the cable supporting the elevator. (b) The elevator continues upward at constant velocity for 8.50 s. What is the tension in the cable during this time? (c) The elevator decelerates at a rate of 0.600 m/s2 for 3.00 s. What is the tension in the cable during deceleration? (d) How high has the elevator moved above its original starting point, and what is its final velocity?What is the tension in the cable supporting the 1700-kg elevator during acceleration from rest at 1.20 m/s^2 for 1.50 s?

a) 2,040 N
b) 3,220 N
c) 4,260 N
d) 5,120 N

Answer 1

The tension in the cable supporting the 1700-kg elevator during acceleration is 2040 N. Therefore the correct answer is a) 2,040 N.

Step-by-step explanation:

To calculate the tension in the cable supporting the 1700-kg elevator, we need to use Newton's second law of motion, which states that force equals mass times acceleration (F = ma).

In this case, the force is the tension in the cable, the mass is 1700 kg, and the acceleration is 1.20 m/s^2. Plugging these values into the equation, we get F = (1700 kg)(1.20 m/s^2) = 2040 N.

Therefore, the tension in the cable supporting the elevator during acceleration is 2040 N.

Tension typically refers to the force transmitted through a rope, cable, or any flexible connector when it's pulled tight by forces acting from opposite ends.

In physics, tension is a pulling force that acts along the length of the rope, string, or similar object. It's directed along the line of the object and away from the object on which the force is applied. When an object is suspended or pulled by a rope or cable, the tension force in the rope is what counteracts the force of gravity acting on the object.