Question

During a wrestling match, a 150 kg wrestler briefly stands on one hand during a maneuver designed to perplex her adversary. By how much does the upper arm bone shorten in length? The bone can be represented by a uniform rod 38.0 cm in length and 2.10 cm in radius.

A. 0.12 , {mm}
B. 0.18 , {mm}
C. 0.24 , {mm}
D. 0.30 , {mm}

Answer 1

The upper arm bone shortens by approximately 0.24 mm when a wrestler stands on one hand.

Step-by-step explanation:

To calculate the change in length of the upper arm bone when a wrestler stands on one hand, we can use the concept of stress and strain in materials. The strain in a rod is given by the ratio of the change in length to the original length. In this case, the upper arm bone can be represented by a uniform rod, and the strain can be calculated using the formula strain = (stress × length) / (Young's modulus × area).

The stress can be calculated using the formula stress = weight / area. Using the given values, the change in length of the upper arm bone is approximately 0.24 mm.