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What is the rate of alcohol removal when the concentration is 2.2 × 10^{-2} M?

a) 2.0×10−2mol L−1h−1
b) 3.3×10−2mol L−1h−1
c) 4.4×10−2mol L−1h−1
d) 2.63×10−8mol L−1s−1

1 Answer

2 votes

Final answer:

The rate of alcohol removal when the concentration is 2.2 × 10^{-2} M is determined by the zero order reaction rate constant, which is 2.0 × 10^{-2} mol L^{-1} h^{-1}, corresponding to option (a).

Step-by-step explanation:

The rate of alcohol removal when the concentration is 2.2 × 10^{-2} M can be determined using the given rate constant. Since the degradation of alcohol is a zero order reaction, the rate at which alcohol is removed from the bloodstream is independent of its initial concentration.

Therefore, the rate constant k provided, which is 2.0 × 10^{-2} mol L^{-1} h^{-1}, is directly the rate of removal of alcohol. The answer, in this case, would be option (a) 2.0× 10^{-2}mol L^{-1}h^{-1} as it reflects the given rate constant for a zero order reaction.

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