Final answer:
The instantaneous rate of disappearance of NO in the reaction NO + O3 ⟶ NO2 + O2 is 1.32 × 10^1 M/s. option (A)
Step-by-step explanation:
The question is asking for the instantaneous rate of disappearance of NO in the given reaction. The reaction is first order with respect to both NO and O3, and has a rate constant of 2.20 × 10^7 L/mol/s. The concentration of NO is given as [NO] = 3.3 × 10^-6 M, and the concentration of O3 is given as [O3] = 5.9 × 10^-7 M. To calculate the instantaneous rate of disappearance of NO, we can use the rate law:
Rate = k[NO][O3]
Substituting the given values:
Rate = (2.20 × 10^7 L/mol/s)(3.3 × 10^-6 M)(5.9 × 10^-7 M)
Rate = 1.32 × 10^1 M/s